65 lines
1.6 KiB
Lua
65 lines
1.6 KiB
Lua
return [=[
|
|
template <ll M>
|
|
void ntt(vector<MLL<M>>& y, bool idft) {
|
|
using mll = MLL<M>;
|
|
|
|
int n = y.size();
|
|
vector<int> rev(n);
|
|
for (int i = 0; i < n; ++i) {
|
|
rev[i] = rev[i >> 1] >> 1;
|
|
if (i & 1) {
|
|
rev[i] |= n >> 1;
|
|
}
|
|
}
|
|
for (int i = 0; i < n; ++i) {
|
|
if (i < rev[i]) {
|
|
swap(y[i], y[rev[i]]);
|
|
}
|
|
}
|
|
vector<mll> roots = { 0, 1 };
|
|
if (roots.size() < n) {
|
|
int k = lsp(roots.size());
|
|
roots.resize(n);
|
|
for (; (1 << k) < n; ++k) {
|
|
mll e = qpow<mll>(31, 1 << lsp(M - 1) - k - 1);
|
|
for (int i = 1 << k - 1; i < (1 << k); ++i) {
|
|
roots[2 * i] = roots[i];
|
|
roots[2 * i + 1] = roots[i] * e;
|
|
}
|
|
}
|
|
}
|
|
for (int h = 2; h <= n; h <<= 1) {
|
|
for (int j = 0; j < n; j += h) {
|
|
for (int k = j; k < j + h / 2; ++k) {
|
|
mll u = y[k], t = roots[k - j + h / 2] * y[k + h / 2];
|
|
y[k] = u + t;
|
|
y[k + h / 2] = u - t;
|
|
}
|
|
}
|
|
}
|
|
if (idft) {
|
|
reverse(y.begin() + 1, y.end());
|
|
for (int i = 0; i < n; ++i) {
|
|
y[i] /= n;
|
|
}
|
|
}
|
|
}
|
|
|
|
template <ll M>
|
|
vector<MLL<M>> multiply(const vector<MLL<M>>& a, const vector<MLL<M>>& b) {
|
|
using mll = MLL<M>;
|
|
|
|
vector<mll> A(a.begin(), a.end()), B(b.begin(), b.end());
|
|
int n = 1;
|
|
while (n < a.size() + b.size()) n <<= 1;
|
|
A.resize(n), B.resize(n);
|
|
ntt<M>(A, false), ntt<M>(B, false);
|
|
for (int i = 0; i < n; ++i) {
|
|
A[i] *= B[i];
|
|
}
|
|
ntt<M>(A, true);
|
|
return A;
|
|
}
|
|
|
|
]=]
|